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a+b=-38 ab=7\left(-24\right)=-168
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 7p^{2}+ap+bp-24. To find a and b, set up a system to be solved.
1,-168 2,-84 3,-56 4,-42 6,-28 7,-24 8,-21 12,-14
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -168.
1-168=-167 2-84=-82 3-56=-53 4-42=-38 6-28=-22 7-24=-17 8-21=-13 12-14=-2
Calculate the sum for each pair.
a=-42 b=4
The solution is the pair that gives sum -38.
\left(7p^{2}-42p\right)+\left(4p-24\right)
Rewrite 7p^{2}-38p-24 as \left(7p^{2}-42p\right)+\left(4p-24\right).
7p\left(p-6\right)+4\left(p-6\right)
Factor out 7p in the first and 4 in the second group.
\left(p-6\right)\left(7p+4\right)
Factor out common term p-6 by using distributive property.
p=6 p=-\frac{4}{7}
To find equation solutions, solve p-6=0 and 7p+4=0.
7p^{2}-38p-24=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
p=\frac{-\left(-38\right)±\sqrt{\left(-38\right)^{2}-4\times 7\left(-24\right)}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, -38 for b, and -24 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
p=\frac{-\left(-38\right)±\sqrt{1444-4\times 7\left(-24\right)}}{2\times 7}
Square -38.
p=\frac{-\left(-38\right)±\sqrt{1444-28\left(-24\right)}}{2\times 7}
Multiply -4 times 7.
p=\frac{-\left(-38\right)±\sqrt{1444+672}}{2\times 7}
Multiply -28 times -24.
p=\frac{-\left(-38\right)±\sqrt{2116}}{2\times 7}
Add 1444 to 672.
p=\frac{-\left(-38\right)±46}{2\times 7}
Take the square root of 2116.
p=\frac{38±46}{2\times 7}
The opposite of -38 is 38.
p=\frac{38±46}{14}
Multiply 2 times 7.
p=\frac{84}{14}
Now solve the equation p=\frac{38±46}{14} when ± is plus. Add 38 to 46.
p=6
Divide 84 by 14.
p=-\frac{8}{14}
Now solve the equation p=\frac{38±46}{14} when ± is minus. Subtract 46 from 38.
p=-\frac{4}{7}
Reduce the fraction \frac{-8}{14} to lowest terms by extracting and canceling out 2.
p=6 p=-\frac{4}{7}
The equation is now solved.
7p^{2}-38p-24=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
7p^{2}-38p-24-\left(-24\right)=-\left(-24\right)
Add 24 to both sides of the equation.
7p^{2}-38p=-\left(-24\right)
Subtracting -24 from itself leaves 0.
7p^{2}-38p=24
Subtract -24 from 0.
\frac{7p^{2}-38p}{7}=\frac{24}{7}
Divide both sides by 7.
p^{2}-\frac{38}{7}p=\frac{24}{7}
Dividing by 7 undoes the multiplication by 7.
p^{2}-\frac{38}{7}p+\left(-\frac{19}{7}\right)^{2}=\frac{24}{7}+\left(-\frac{19}{7}\right)^{2}
Divide -\frac{38}{7}, the coefficient of the x term, by 2 to get -\frac{19}{7}. Then add the square of -\frac{19}{7} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
p^{2}-\frac{38}{7}p+\frac{361}{49}=\frac{24}{7}+\frac{361}{49}
Square -\frac{19}{7} by squaring both the numerator and the denominator of the fraction.
p^{2}-\frac{38}{7}p+\frac{361}{49}=\frac{529}{49}
Add \frac{24}{7} to \frac{361}{49} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(p-\frac{19}{7}\right)^{2}=\frac{529}{49}
Factor p^{2}-\frac{38}{7}p+\frac{361}{49}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(p-\frac{19}{7}\right)^{2}}=\sqrt{\frac{529}{49}}
Take the square root of both sides of the equation.
p-\frac{19}{7}=\frac{23}{7} p-\frac{19}{7}=-\frac{23}{7}
Simplify.
p=6 p=-\frac{4}{7}
Add \frac{19}{7} to both sides of the equation.
x ^ 2 -\frac{38}{7}x -\frac{24}{7} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 7
r + s = \frac{38}{7} rs = -\frac{24}{7}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{19}{7} - u s = \frac{19}{7} + u
Two numbers r and s sum up to \frac{38}{7} exactly when the average of the two numbers is \frac{1}{2}*\frac{38}{7} = \frac{19}{7}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{19}{7} - u) (\frac{19}{7} + u) = -\frac{24}{7}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{24}{7}
\frac{361}{49} - u^2 = -\frac{24}{7}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{24}{7}-\frac{361}{49} = -\frac{529}{49}
Simplify the expression by subtracting \frac{361}{49} on both sides
u^2 = \frac{529}{49} u = \pm\sqrt{\frac{529}{49}} = \pm \frac{23}{7}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{19}{7} - \frac{23}{7} = -0.571 s = \frac{19}{7} + \frac{23}{7} = 6
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.