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7m^{2}-21m=0
Subtract 21m from both sides.
m\left(7m-21\right)=0
Factor out m.
m=0 m=3
To find equation solutions, solve m=0 and 7m-21=0.
7m^{2}-21m=0
Subtract 21m from both sides.
m=\frac{-\left(-21\right)±\sqrt{\left(-21\right)^{2}}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, -21 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-\left(-21\right)±21}{2\times 7}
Take the square root of \left(-21\right)^{2}.
m=\frac{21±21}{2\times 7}
The opposite of -21 is 21.
m=\frac{21±21}{14}
Multiply 2 times 7.
m=\frac{42}{14}
Now solve the equation m=\frac{21±21}{14} when ± is plus. Add 21 to 21.
m=3
Divide 42 by 14.
m=\frac{0}{14}
Now solve the equation m=\frac{21±21}{14} when ± is minus. Subtract 21 from 21.
m=0
Divide 0 by 14.
m=3 m=0
The equation is now solved.
7m^{2}-21m=0
Subtract 21m from both sides.
\frac{7m^{2}-21m}{7}=\frac{0}{7}
Divide both sides by 7.
m^{2}+\left(-\frac{21}{7}\right)m=\frac{0}{7}
Dividing by 7 undoes the multiplication by 7.
m^{2}-3m=\frac{0}{7}
Divide -21 by 7.
m^{2}-3m=0
Divide 0 by 7.
m^{2}-3m+\left(-\frac{3}{2}\right)^{2}=\left(-\frac{3}{2}\right)^{2}
Divide -3, the coefficient of the x term, by 2 to get -\frac{3}{2}. Then add the square of -\frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
m^{2}-3m+\frac{9}{4}=\frac{9}{4}
Square -\frac{3}{2} by squaring both the numerator and the denominator of the fraction.
\left(m-\frac{3}{2}\right)^{2}=\frac{9}{4}
Factor m^{2}-3m+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m-\frac{3}{2}\right)^{2}}=\sqrt{\frac{9}{4}}
Take the square root of both sides of the equation.
m-\frac{3}{2}=\frac{3}{2} m-\frac{3}{2}=-\frac{3}{2}
Simplify.
m=3 m=0
Add \frac{3}{2} to both sides of the equation.