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-3x^{2}-2x+7=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\left(-3\right)\times 7}}{2\left(-3\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-2\right)±\sqrt{4-4\left(-3\right)\times 7}}{2\left(-3\right)}
Square -2.
x=\frac{-\left(-2\right)±\sqrt{4+12\times 7}}{2\left(-3\right)}
Multiply -4 times -3.
x=\frac{-\left(-2\right)±\sqrt{4+84}}{2\left(-3\right)}
Multiply 12 times 7.
x=\frac{-\left(-2\right)±\sqrt{88}}{2\left(-3\right)}
Add 4 to 84.
x=\frac{-\left(-2\right)±2\sqrt{22}}{2\left(-3\right)}
Take the square root of 88.
x=\frac{2±2\sqrt{22}}{2\left(-3\right)}
The opposite of -2 is 2.
x=\frac{2±2\sqrt{22}}{-6}
Multiply 2 times -3.
x=\frac{2\sqrt{22}+2}{-6}
Now solve the equation x=\frac{2±2\sqrt{22}}{-6} when ± is plus. Add 2 to 2\sqrt{22}.
x=\frac{-\sqrt{22}-1}{3}
Divide 2+2\sqrt{22} by -6.
x=\frac{2-2\sqrt{22}}{-6}
Now solve the equation x=\frac{2±2\sqrt{22}}{-6} when ± is minus. Subtract 2\sqrt{22} from 2.
x=\frac{\sqrt{22}-1}{3}
Divide 2-2\sqrt{22} by -6.
-3x^{2}-2x+7=-3\left(x-\frac{-\sqrt{22}-1}{3}\right)\left(x-\frac{\sqrt{22}-1}{3}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-1-\sqrt{22}}{3} for x_{1} and \frac{-1+\sqrt{22}}{3} for x_{2}.