Solve 7x^2+13y=-39

$$7 { x }^{ 2 } +13y=-39$$

Solve for y

$$y=-\frac{7x^{2}}{13}-3$$

Steps for Solving Linear Equation

Subtract 7x^{2} from both sides.

$$13y=-39-7x^{2}$$

The equation is in standard form.

$$13y=-7x^{2}-39$$

Divide both sides by 13.

$$\frac{13y}{13}=\frac{-7x^{2}-39}{13}$$

Dividing by 13 undoes the multiplication by 13.

$$y=\frac{-7x^{2}-39}{13}$$

Divide -39-7x^{2} by 13.

$$y=-\frac{7x^{2}}{13}-3$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-91y-273}}{7}$$

$$x=\frac{\sqrt{-91y-273}}{7}$$

Solve for x

$$x=\frac{\sqrt{-91y-273}}{7}$$

$$x=-\frac{\sqrt{-91y-273}}{7}\text{, }y\leq -3$$