Solve 7*43div12.3*6+18div14.7*41=

$$7 \times 43 \div 12.3 \times 6 + 18 \div 14.7 \times 41 =$$

Evaluate

$$\frac{395840}{2009}\approx 197.033349925$$

Solution Steps

Multiply 7 and 43 to get 301.

$$\frac{301}{12.3}\times 6+\frac{18}{14.7}\times 41$$

Expand \frac{301}{12.3} by multiplying both numerator and the denominator by 10.

$$\frac{3010}{123}\times 6+\frac{18}{14.7}\times 41$$

Express \frac{3010}{123}\times 6 as a single fraction.

$$\frac{3010\times 6}{123}+\frac{18}{14.7}\times 41$$

Multiply 3010 and 6 to get 18060.

$$\frac{18060}{123}+\frac{18}{14.7}\times 41$$

Reduce the fraction \frac{18060}{123} to lowest terms by extracting and canceling out 3.

$$\frac{6020}{41}+\frac{18}{14.7}\times 41$$

Expand \frac{18}{14.7} by multiplying both numerator and the denominator by 10.

$$\frac{6020}{41}+\frac{180}{147}\times 41$$

Reduce the fraction \frac{180}{147} to lowest terms by extracting and canceling out 3.

$$\frac{6020}{41}+\frac{60}{49}\times 41$$

Express \frac{60}{49}\times 41 as a single fraction.

$$\frac{6020}{41}+\frac{60\times 41}{49}$$

Multiply 60 and 41 to get 2460.

$$\frac{6020}{41}+\frac{2460}{49}$$

Least common multiple of 41 and 49 is 2009. Convert \frac{6020}{41} and \frac{2460}{49} to fractions with denominator 2009.

$$\frac{294980}{2009}+\frac{100860}{2009}$$

Since \frac{294980}{2009} and \frac{100860}{2009} have the same denominator, add them by adding their numerators.

$$\frac{294980+100860}{2009}$$

Add 294980 and 100860 to get 395840.

$$\frac{395840}{2009}$$

Factor

$$\frac{5 \cdot 1237 \cdot 2 ^ {6}}{41 \cdot 7 ^ {2}} = 197\frac{67}{2009} = 197.03334992533598$$