Solve 7*2div8+4-3*2

$$7 \times 2 \div 8+4-3 \times 2$$

Evaluate

$$-\frac{1}{4}=-0.25$$

Solution Steps

Multiply 7 and 2 to get 14.

$$\frac{14}{8}+4-3\times 2$$

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$\frac{7}{4}+4-3\times 2$$

Convert 4 to fraction \frac{16}{4}.

$$\frac{7}{4}+\frac{16}{4}-3\times 2$$

Since \frac{7}{4} and \frac{16}{4} have the same denominator, add them by adding their numerators.

$$\frac{7+16}{4}-3\times 2$$

Add 7 and 16 to get 23.

$$\frac{23}{4}-3\times 2$$

Multiply 3 and 2 to get 6.

$$\frac{23}{4}-6$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{23}{4}-\frac{24}{4}$$

Since \frac{23}{4} and \frac{24}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{23-24}{4}$$

Subtract 24 from 23 to get -1.

$$-\frac{1}{4}$$

Factor

$$-\frac{1}{4} = -0.25$$