Solve 71/6-(0.35+21/6)

$$7 \frac { 1 } { 6 } - ( 0.35 + 2 \frac { 1 } { 6 } )$$

Evaluate

$$4.65$$

Solution Steps

Multiply 7 and 6 to get 42.

$$\frac{42+1}{6}-\left(0.35+\frac{2\times 6+1}{6}\right)$$

Add 42 and 1 to get 43.

$$\frac{43}{6}-\left(0.35+\frac{2\times 6+1}{6}\right)$$

Multiply 2 and 6 to get 12.

$$\frac{43}{6}-\left(0.35+\frac{12+1}{6}\right)$$

Add 12 and 1 to get 13.

$$\frac{43}{6}-\left(0.35+\frac{13}{6}\right)$$

Convert decimal number 0.35 to fraction \frac{35}{100}. Reduce the fraction \frac{35}{100} to lowest terms by extracting and canceling out 5.

$$\frac{43}{6}-\left(\frac{7}{20}+\frac{13}{6}\right)$$

Least common multiple of 20 and 6 is 60. Convert \frac{7}{20} and \frac{13}{6} to fractions with denominator 60.

$$\frac{43}{6}-\left(\frac{21}{60}+\frac{130}{60}\right)$$

Since \frac{21}{60} and \frac{130}{60} have the same denominator, add them by adding their numerators.

$$\frac{43}{6}-\frac{21+130}{60}$$

Add 21 and 130 to get 151.

$$\frac{43}{6}-\frac{151}{60}$$

Least common multiple of 6 and 60 is 60. Convert \frac{43}{6} and \frac{151}{60} to fractions with denominator 60.

$$\frac{430}{60}-\frac{151}{60}$$

Since \frac{430}{60} and \frac{151}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{430-151}{60}$$

Subtract 151 from 430 to get 279.

$$\frac{279}{60}$$

Reduce the fraction \frac{279}{60} to lowest terms by extracting and canceling out 3.

$$\frac{93}{20}$$

Factor

$$\frac{3 \cdot 31}{5 \cdot 2 ^ {2}} = 4\frac{13}{20} = 4.65$$