Solve 71/3div21/5

$$7 \frac { 1 } { 3 } \div 2 \frac { 1 } { 5 }$$

Evaluate

$$\frac{10}{3}\approx 3.333333333$$

Solution Steps

Divide \frac{7\times 3+1}{3} by \frac{2\times 5+1}{5} by multiplying \frac{7\times 3+1}{3} by the reciprocal of \frac{2\times 5+1}{5}.

$$\frac{\left(7\times 3+1\right)\times 5}{3\left(2\times 5+1\right)}$$

Multiply 7 and 3 to get 21.

$$\frac{\left(21+1\right)\times 5}{3\left(2\times 5+1\right)}$$

Add 21 and 1 to get 22.

$$\frac{22\times 5}{3\left(2\times 5+1\right)}$$

Multiply 22 and 5 to get 110.

$$\frac{110}{3\left(2\times 5+1\right)}$$

Multiply 2 and 5 to get 10.

$$\frac{110}{3\left(10+1\right)}$$

Add 10 and 1 to get 11.

$$\frac{110}{3\times 11}$$

Multiply 3 and 11 to get 33.

$$\frac{110}{33}$$

Reduce the fraction \frac{110}{33} to lowest terms by extracting and canceling out 11.

$$\frac{10}{3}$$

Factor

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$