Solve 71/3+11/2=

$$7 \frac { 1 } { 3 } + 1 \frac { 1 } { 2 } =$$

Evaluate

$$\frac{53}{6}\approx 8.833333333$$

Solution Steps

Multiply 7 and 3 to get 21.

$$\frac{21+1}{3}+\frac{1\times 2+1}{2}$$

Add 21 and 1 to get 22.

$$\frac{22}{3}+\frac{1\times 2+1}{2}$$

Multiply 1 and 2 to get 2.

$$\frac{22}{3}+\frac{2+1}{2}$$

Add 2 and 1 to get 3.

$$\frac{22}{3}+\frac{3}{2}$$

Least common multiple of 3 and 2 is 6. Convert \frac{22}{3} and \frac{3}{2} to fractions with denominator 6.

$$\frac{44}{6}+\frac{9}{6}$$

Since \frac{44}{6} and \frac{9}{6} have the same denominator, add them by adding their numerators.

$$\frac{44+9}{6}$$

Add 44 and 9 to get 53.

$$\frac{53}{6}$$

Factor

$$\frac{53}{2 \cdot 3} = 8\frac{5}{6} = 8.833333333333334$$