Solve 71/2+11/3

$$7 \frac { 1 } { 2 } + 1 \frac { 1 } { 3 }$$

Evaluate

$$\frac{53}{6}\approx 8.833333333$$

Solution Steps

Multiply 7 and 2 to get 14.

$$\frac{14+1}{2}+\frac{1\times 3+1}{3}$$

Add 14 and 1 to get 15.

$$\frac{15}{2}+\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{15}{2}+\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{15}{2}+\frac{4}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{15}{2} and \frac{4}{3} to fractions with denominator 6.

$$\frac{45}{6}+\frac{8}{6}$$

Since \frac{45}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.

$$\frac{45+8}{6}$$

Add 45 and 8 to get 53.

$$\frac{53}{6}$$

Factor

$$\frac{53}{2 \cdot 3} = 8\frac{5}{6} = 8.833333333333334$$