Solve 7div6+3div3+12div18

$$7 \div 6+3 \div 3+12 \div 18$$

Evaluate

$$\frac{17}{6}\approx 2.833333333$$

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{7}{6}+1+\frac{12}{18}$$

Convert 1 to fraction \frac{6}{6}.

$$\frac{7}{6}+\frac{6}{6}+\frac{12}{18}$$

Since \frac{7}{6} and \frac{6}{6} have the same denominator, add them by adding their numerators.

$$\frac{7+6}{6}+\frac{12}{18}$$

Add 7 and 6 to get 13.

$$\frac{13}{6}+\frac{12}{18}$$

Reduce the fraction \frac{12}{18} to lowest terms by extracting and canceling out 6.

$$\frac{13}{6}+\frac{2}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{13}{6} and \frac{2}{3} to fractions with denominator 6.

$$\frac{13}{6}+\frac{4}{6}$$

Since \frac{13}{6} and \frac{4}{6} have the same denominator, add them by adding their numerators.

$$\frac{13+4}{6}$$

Add 13 and 4 to get 17.

$$\frac{17}{6}$$

Factor

$$\frac{17}{2 \cdot 3} = 2\frac{5}{6} = 2.8333333333333335$$