Solve 7*10^0+4*10^-1+1*10^-3

$$7 \cdot 10 ^ { 0 } + 4 \cdot 10 ^ { - 1 } + 1 \cdot 10 ^ { - 3 }$$

Evaluate

$$\frac{7401}{1000}=7.401$$

Solution Steps

Calculate 10 to the power of 0 and get 1.

$$7\times 1+4\times 10^{-1}+1\times 10^{-3}$$

Multiply 7 and 1 to get 7.

$$7+4\times 10^{-1}+1\times 10^{-3}$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$7+4\times \frac{1}{10}+1\times 10^{-3}$$

Multiply 4 and \frac{1}{10} to get \frac{2}{5}.

$$7+\frac{2}{5}+1\times 10^{-3}$$

Add 7 and \frac{2}{5} to get \frac{37}{5}.

$$\frac{37}{5}+1\times 10^{-3}$$

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$\frac{37}{5}+1\times \frac{1}{1000}$$

Multiply 1 and \frac{1}{1000} to get \frac{1}{1000}.

$$\frac{37}{5}+\frac{1}{1000}$$

Add \frac{37}{5} and \frac{1}{1000} to get \frac{7401}{1000}.

$$\frac{7401}{1000}$$

Factor

$$\frac{3 \cdot 2467}{2 ^ {3} \cdot 5 ^ {3}} = 7\frac{401}{1000} = 7.401$$