Solve 7^2div7+5^2div5-4^2div4=

$$7 ^ { 2 } \div 7 + 5 ^ { 2 } \div 5 - 4 ^ { 2 } \div 4 =$$

Evaluate

$$8$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$7^{1}+\frac{5^{2}}{5}-\frac{4^{2}}{4}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$7^{1}+5^{1}-\frac{4^{2}}{4}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$7^{1}+5^{1}-4^{1}$$

Calculate 7 to the power of 1 and get 7.

$$7+5^{1}-4^{1}$$

Calculate 5 to the power of 1 and get 5.

$$7+5-4^{1}$$

Add 7 and 5 to get 12.

$$12-4^{1}$$

Calculate 4 to the power of 1 and get 4.

$$12-4$$

Subtract 4 from 12 to get 8.

$$8$$

Factor

$$2^{3}$$