Solve 7:-1^4-1/7div[16-(-3)^2]

$$7 : - 1 ^ { 4 } - \frac { 1 } { 7 } \div [ 16 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$-\frac{344}{49}\approx -7.020408163$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$\frac{7}{-1}-\frac{\frac{1}{7}}{16-\left(-3\right)^{2}}$$

Fraction \frac{7}{-1} can be rewritten as -7 by extracting the negative sign.

$$-7-\frac{\frac{1}{7}}{16-\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$-7-\frac{\frac{1}{7}}{16-9}$$

Subtract 9 from 16 to get 7.

$$-7-\frac{\frac{1}{7}}{7}$$

Express \frac{\frac{1}{7}}{7} as a single fraction.

$$-7-\frac{1}{7\times 7}$$

Multiply 7 and 7 to get 49.

$$-7-\frac{1}{49}$$

Convert -7 to fraction -\frac{343}{49}.

$$-\frac{343}{49}-\frac{1}{49}$$

Since -\frac{343}{49} and \frac{1}{49} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-343-1}{49}$$

Subtract 1 from -343 to get -344.

$$-\frac{344}{49}$$

Factor

$$-\frac{344}{49} = -7\frac{1}{49} = -7.020408163265306$$