Solve for x
x=\frac{y+12}{6}
Solve for y
y=6\left(x-2\right)
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6x-12=y
Add y to both sides. Anything plus zero gives itself.
6x=y+12
Add 12 to both sides.
\frac{6x}{6}=\frac{y+12}{6}
Divide both sides by 6.
x=\frac{y+12}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{y}{6}+2
Divide y+12 by 6.
-y-12=-6x
Subtract 6x from both sides. Anything subtracted from zero gives its negation.
-y=-6x+12
Add 12 to both sides.
-y=12-6x
The equation is in standard form.
\frac{-y}{-1}=\frac{12-6x}{-1}
Divide both sides by -1.
y=\frac{12-6x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=6x-12
Divide -6x+12 by -1.
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Limits
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