Factor
\left(4a-1\right)\left(16a^{2}+4a+1\right)
Evaluate
64a^{3}-1
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\left(4a-1\right)\left(16a^{2}+4a+1\right)
Rewrite 64a^{3}-1 as \left(4a\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right). Polynomial 16a^{2}+4a+1 is not factored since it does not have any rational roots.
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