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8\left(8-x^{3}\right)
Factor out 8.
\left(x-2\right)\left(-x^{2}-2x-4\right)
Consider 8-x^{3}. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 8 and q divides the leading coefficient -1. One such root is 2. Factor the polynomial by dividing it by x-2.
8\left(x-2\right)\left(-x^{2}-2x-4\right)
Rewrite the complete factored expression. Polynomial -x^{2}-2x-4 is not factored since it does not have any rational roots.