Solve 64^frac{2{3}}*6d5^frac{1{4}}-36^2*32^frac{1{3}}=

$$64 ^ { \frac { 2 } { 3 } } \cdot 6 d 5 ^ { \frac { 1 } { 4 } } - 36 ^ { 2 } \cdot 32 ^ { \frac { 1 } { 3 } } =$$

Evaluate

$$96\left(\sqrt[4]{5}d-27\times 2^{\frac{2}{3}}\right)$$

Solution Steps

Calculate 64 to the power of \frac{2}{3} and get 16.

$$16\times 6d\times 5^{\frac{1}{4}}-36^{2}\times 32^{\frac{1}{3}}$$

Multiply 16 and 6 to get 96.

$$96d\times 5^{\frac{1}{4}}-36^{2}\times 32^{\frac{1}{3}}$$

Calculate 36 to the power of 2 and get 1296.

$$96d\times 5^{\frac{1}{4}}-1296\times 32^{\frac{1}{3}}$$

Factor

$$96\left(\sqrt[4]{5}d-27\times 2^{\frac{2}{3}}\right)$$

Solution Steps

Factor out 6.

$$6\left(16d\sqrt[4]{5}-432\sqrt[3]{4}\right)$$