Solve for a
a=\frac{64}{3^{b}}
Solve for b
b=\frac{-\ln(a)+6\ln(2)}{\ln(3)}
a>0
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a\times 3^{b}=64
Swap sides so that all variable terms are on the left hand side.
3^{b}a=64
The equation is in standard form.
\frac{3^{b}a}{3^{b}}=\frac{64}{3^{b}}
Divide both sides by 3^{b}.
a=\frac{64}{3^{b}}
Dividing by 3^{b} undoes the multiplication by 3^{b}.
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