Solve 631/3+45/6)div(45/6-2)

$$63 \frac { 1 } { 3 } + 4 \frac { 5 } { 6 } ) \div ( 4 \frac { 5 } { 6 } - 2 )$$

Evaluate

$$\frac{409}{6}\approx 68.166666667$$

Solution Steps

Multiply 63 and 3 to get 189.

$$\frac{189+1}{3}+\frac{4\times 6+5}{6}$$

Add 189 and 1 to get 190.

$$\frac{190}{3}+\frac{4\times 6+5}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{190}{3}+\frac{24+5}{6}$$

Add 24 and 5 to get 29.

$$\frac{190}{3}+\frac{29}{6}$$

Least common multiple of 3 and 6 is 6. Convert \frac{190}{3} and \frac{29}{6} to fractions with denominator 6.

$$\frac{380}{6}+\frac{29}{6}$$

Since \frac{380}{6} and \frac{29}{6} have the same denominator, add them by adding their numerators.

$$\frac{380+29}{6}$$

Add 380 and 29 to get 409.

$$\frac{409}{6}$$

Factor

$$\frac{409}{2 \cdot 3} = 68\frac{1}{6} = 68.16666666666667$$