Solve 6160:{20[7+18:(12-3)]}-[70*3*18:2-1]

$$6160 : \{ 20 [ 7 + 18 : ( 12 - 3 ) ] \} - [ 70 \cdot 3 \cdot 18 : 2 - 1 ]$$

Evaluate

$$-\frac{16693}{9}\approx -1854.777777778$$

Solution Steps

Subtract 3 from 12 to get 9.

$$\frac{6160}{20\left(7+\frac{18}{9}\right)}-\left(\frac{70\times 3\times 18}{2}-1\right)$$

Divide 18 by 9 to get 2.

$$\frac{6160}{20\left(7+2\right)}-\left(\frac{70\times 3\times 18}{2}-1\right)$$

Add 7 and 2 to get 9.

$$\frac{6160}{20\times 9}-\left(\frac{70\times 3\times 18}{2}-1\right)$$

Multiply 20 and 9 to get 180.

$$\frac{6160}{180}-\left(\frac{70\times 3\times 18}{2}-1\right)$$

Reduce the fraction \frac{6160}{180} to lowest terms by extracting and canceling out 20.

$$\frac{308}{9}-\left(\frac{70\times 3\times 18}{2}-1\right)$$

Multiply 70 and 3 to get 210.

$$\frac{308}{9}-\left(\frac{210\times 18}{2}-1\right)$$

Multiply 210 and 18 to get 3780.

$$\frac{308}{9}-\left(\frac{3780}{2}-1\right)$$

Divide 3780 by 2 to get 1890.

$$\frac{308}{9}-\left(1890-1\right)$$

Subtract 1 from 1890 to get 1889.

$$\frac{308}{9}-1889$$

Convert 1889 to fraction \frac{17001}{9}.

$$\frac{308}{9}-\frac{17001}{9}$$

Since \frac{308}{9} and \frac{17001}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{308-17001}{9}$$

Subtract 17001 from 308 to get -16693.

$$-\frac{16693}{9}$$

Factor

$$-\frac{16693}{9} = -1854\frac{7}{9} = -1854.7777777777778$$