Solve 60+.6xleq.8x

$$60+.6x \leq .8x$$

Solve for x

$$x\geq 300$$

Solution Steps

Subtract 0.8x from both sides.

$$60+0.6x-0.8x\leq 0$$

Combine 0.6x and -0.8x to get -0.2x.

$$60-0.2x\leq 0$$

Subtract 60 from both sides. Anything subtracted from zero gives its negation.

$$-0.2x\leq -60$$

Divide both sides by -0.2. Since -0.2 is negative, the inequality direction is changed.

$$x\geq \frac{-60}{-0.2}$$

Expand \frac{-60}{-0.2} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{-600}{-2}$$

Divide -600 by -2 to get 300.

$$x\geq 300$$