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6\left(10y^{4}-50y^{3}-7y^{2}+35y\right)
Factor out 6.
y\left(10y^{3}-50y^{2}-7y+35\right)
Consider 10y^{4}-50y^{3}-7y^{2}+35y. Factor out y.
10y^{2}\left(y-5\right)-7\left(y-5\right)
Consider 10y^{3}-50y^{2}-7y+35. Do the grouping 10y^{3}-50y^{2}-7y+35=\left(10y^{3}-50y^{2}\right)+\left(-7y+35\right), and factor out 10y^{2} in the first and -7 in the second group.
\left(y-5\right)\left(10y^{2}-7\right)
Factor out common term y-5 by using distributive property.
6y\left(y-5\right)\left(10y^{2}-7\right)
Rewrite the complete factored expression. Polynomial 10y^{2}-7 is not factored since it does not have any rational roots.