Solve 60left(1+xright)^2=72.6

$$60 { \left(1+x \right) }^{ 2 } =72.6$$

Solve for x

$$x=0.1$$

$$x=-2.1$$

Steps by Finding Square Root

Divide both sides by 60.

$$\frac{60\left(x+1\right)^{2}}{60}=\frac{72.6}{60}$$

Dividing by 60 undoes the multiplication by 60.

$$\left(x+1\right)^{2}=\frac{72.6}{60}$$

Divide 72.6 by 60.

$$\left(x+1\right)^{2}=1.21$$

Take the square root of both sides of the equation.

$$x+1=\frac{11}{10} x+1=-\frac{11}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{11}{10}-1 x+1-1=-\frac{11}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{11}{10}-1 x=-\frac{11}{10}-1$$

Subtract 1 from \frac{11}{10}.

$$x=\frac{1}{10}$$

Subtract 1 from -\frac{11}{10}.

$$x=-\frac{21}{10}$$

The equation is now solved.

$$x=\frac{1}{10} x=-\frac{21}{10}$$