Solve 6-2-1.4/4+4.2/8-9left(7/9+1.4/3right)=2-1.4

$$6-2- \frac{ 1.4 }{ 4 } + \frac{ 4.2 }{ 8 } -9 \left( \frac{ 7 }{ 9 } + \frac{ 1.4 }{ 3 } \right) = 2-1.4$$

Verify

Solution Steps

Subtract 2 from 6 to get 4.

$$4-\frac{1.4}{4}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Expand \frac{1.4}{4} by multiplying both numerator and the denominator by 10.

$$4-\frac{14}{40}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Reduce the fraction \frac{14}{40} to lowest terms by extracting and canceling out 2.

$$4-\frac{7}{20}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Convert 4 to fraction \frac{80}{20}.

$$\frac{80}{20}-\frac{7}{20}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Since \frac{80}{20} and \frac{7}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{80-7}{20}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Subtract 7 from 80 to get 73.

$$\frac{73}{20}+\frac{4.2}{8}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Expand \frac{4.2}{8} by multiplying both numerator and the denominator by 10.

$$\frac{73}{20}+\frac{42}{80}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Reduce the fraction \frac{42}{80} to lowest terms by extracting and canceling out 2.

$$\frac{73}{20}+\frac{21}{40}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Least common multiple of 20 and 40 is 40. Convert \frac{73}{20} and \frac{21}{40} to fractions with denominator 40.

$$\frac{146}{40}+\frac{21}{40}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Since \frac{146}{40} and \frac{21}{40} have the same denominator, add them by adding their numerators.

$$\frac{146+21}{40}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Add 146 and 21 to get 167.

$$\frac{167}{40}-9\left(\frac{7}{9}+\frac{1.4}{3}\right)=2-1.4$$

Expand \frac{1.4}{3} by multiplying both numerator and the denominator by 10.

$$\frac{167}{40}-9\left(\frac{7}{9}+\frac{14}{30}\right)=2-1.4$$

Reduce the fraction \frac{14}{30} to lowest terms by extracting and canceling out 2.

$$\frac{167}{40}-9\left(\frac{7}{9}+\frac{7}{15}\right)=2-1.4$$

Least common multiple of 9 and 15 is 45. Convert \frac{7}{9} and \frac{7}{15} to fractions with denominator 45.

$$\frac{167}{40}-9\left(\frac{35}{45}+\frac{21}{45}\right)=2-1.4$$

Since \frac{35}{45} and \frac{21}{45} have the same denominator, add them by adding their numerators.

$$\frac{167}{40}-9\times \frac{35+21}{45}=2-1.4$$

Add 35 and 21 to get 56.

$$\frac{167}{40}-9\times \frac{56}{45}=2-1.4$$

Express 9\times \frac{56}{45} as a single fraction.

$$\frac{167}{40}-\frac{9\times 56}{45}=2-1.4$$

Multiply 9 and 56 to get 504.

$$\frac{167}{40}-\frac{504}{45}=2-1.4$$

Reduce the fraction \frac{504}{45} to lowest terms by extracting and canceling out 9.

$$\frac{167}{40}-\frac{56}{5}=2-1.4$$

Least common multiple of 40 and 5 is 40. Convert \frac{167}{40} and \frac{56}{5} to fractions with denominator 40.

$$\frac{167}{40}-\frac{448}{40}=2-1.4$$

Since \frac{167}{40} and \frac{448}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{167-448}{40}=2-1.4$$

Subtract 448 from 167 to get -281.

$$-\frac{281}{40}=2-1.4$$

Subtract 1.4 from 2 to get 0.6.

$$-\frac{281}{40}=0.6$$

Convert decimal number 0.6 to fraction \frac{6}{10}. Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{281}{40}=\frac{3}{5}$$

Least common multiple of 40 and 5 is 40. Convert -\frac{281}{40} and \frac{3}{5} to fractions with denominator 40.

$$-\frac{281}{40}=\frac{24}{40}$$

Compare -\frac{281}{40} and \frac{24}{40}.

$$\text{false}$$