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-1.2x^{2}=-6
Subtract 6 from both sides. Anything subtracted from zero gives its negation.
x^{2}=\frac{-6}{-1.2}
Divide both sides by -1.2.
x^{2}=\frac{-60}{-12}
Expand \frac{-6}{-1.2} by multiplying both numerator and the denominator by 10.
x^{2}=5
Divide -60 by -12 to get 5.
x=\sqrt{5} x=-\sqrt{5}
Take the square root of both sides of the equation.
-1.2x^{2}+6=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-1.2\right)\times 6}}{2\left(-1.2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1.2 for a, 0 for b, and 6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1.2\right)\times 6}}{2\left(-1.2\right)}
Square 0.
x=\frac{0±\sqrt{4.8\times 6}}{2\left(-1.2\right)}
Multiply -4 times -1.2.
x=\frac{0±\sqrt{28.8}}{2\left(-1.2\right)}
Multiply 4.8 times 6.
x=\frac{0±\frac{12\sqrt{5}}{5}}{2\left(-1.2\right)}
Take the square root of 28.8.
x=\frac{0±\frac{12\sqrt{5}}{5}}{-2.4}
Multiply 2 times -1.2.
x=-\sqrt{5}
Now solve the equation x=\frac{0±\frac{12\sqrt{5}}{5}}{-2.4} when ± is plus.
x=\sqrt{5}
Now solve the equation x=\frac{0±\frac{12\sqrt{5}}{5}}{-2.4} when ± is minus.
x=-\sqrt{5} x=\sqrt{5}
The equation is now solved.