Solve 6(8-3x)=-10

$$6(8-3x)=-10$$

Solve for x

$$x = \frac{29}{9} = 3\frac{2}{9} \approx 3.222222222$$

Steps for Solving Linear Equation

Divide both sides by 6.

$$8-3x=\frac{-10}{6}$$

Reduce the fraction \frac{-10}{6} to lowest terms by extracting and canceling out 2.

$$8-3x=-\frac{5}{3}$$

Subtract 8 from both sides.

$$-3x=-\frac{5}{3}-8$$

Convert 8 to fraction \frac{24}{3}.

$$-3x=-\frac{5}{3}-\frac{24}{3}$$

Since -\frac{5}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$-3x=\frac{-5-24}{3}$$

Subtract 24 from -5 to get -29.

$$-3x=-\frac{29}{3}$$

Divide both sides by -3.

$$x=\frac{-\frac{29}{3}}{-3}$$

Express \frac{-\frac{29}{3}}{-3} as a single fraction.

$$x=\frac{-29}{3\left(-3\right)}$$

Multiply 3 and -3 to get -9.

$$x=\frac{-29}{-9}$$

Fraction \frac{-29}{-9} can be simplified to \frac{29}{9} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{29}{9}$$