Solve 6(-30x+600)leq900

$$6(-30x+600) \leq 900$$

Solve for x

$$x\geq 15$$

Solution Steps

Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.

$$-30x+600\leq \frac{900}{6}$$

Divide 900 by 6 to get 150.

$$-30x+600\leq 150$$

Subtract 600 from both sides.

$$-30x\leq 150-600$$

Subtract 600 from 150 to get -450.

$$-30x\leq -450$$

Divide both sides by -30. Since -30 is negative, the inequality direction is changed.

$$x\geq \frac{-450}{-30}$$

Divide -450 by -30 to get 15.

$$x\geq 15$$