Solve 6+(3x-left(3+4x-1right)9)=-2

$$6+(3x- \left( 3+4x-1 \right) 9) = -2$$

Solve for x

$$x=-\frac{10}{33}\approx -0.303030303$$

Steps for Solving Linear Equation

Subtract 1 from 3 to get 2.

$$6+3x-\left(2+4x\right)\times 9=-2$$

Use the distributive property to multiply 2+4x by 9.

$$6+3x-\left(18+36x\right)=-2$$

To find the opposite of 18+36x, find the opposite of each term.

$$6+3x-18-36x=-2$$

Combine 3x and -36x to get -33x.

$$6-33x-18=-2$$

Subtract 18 from 6 to get -12.

$$-12-33x=-2$$

Add 12 to both sides.

$$-33x=-2+12$$

Add -2 and 12 to get 10.

$$-33x=10$$

Divide both sides by -33.

$$x=\frac{10}{-33}$$

Fraction \frac{10}{-33} can be rewritten as -\frac{10}{33} by extracting the negative sign.

$$x=-\frac{10}{33}$$