Solve for y
y=-\frac{x^{3}}{6}-\frac{x^{2}}{2}+\frac{1}{3}
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6y=2-3x^{2}-x^{3}
The equation is in standard form.
\frac{6y}{6}=\frac{2-3x^{2}-x^{3}}{6}
Divide both sides by 6.
y=\frac{2-3x^{2}-x^{3}}{6}
Dividing by 6 undoes the multiplication by 6.
y=-\frac{x^{3}}{6}-\frac{x^{2}}{2}+\frac{1}{3}
Divide 2-3x^{2}-x^{3} by 6.
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