Solve for x
x=\frac{3y}{2}-\frac{1}{6}
Solve for y
y=\frac{2x}{3}+\frac{1}{9}
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6x=-1+9y
Add 9y to both sides.
6x=9y-1
The equation is in standard form.
\frac{6x}{6}=\frac{9y-1}{6}
Divide both sides by 6.
x=\frac{9y-1}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{3y}{2}-\frac{1}{6}
Divide -1+9y by 6.
-9y=-1-6x
Subtract 6x from both sides.
-9y=-6x-1
The equation is in standard form.
\frac{-9y}{-9}=\frac{-6x-1}{-9}
Divide both sides by -9.
y=\frac{-6x-1}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{2x}{3}+\frac{1}{9}
Divide -1-6x by -9.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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