Solve for x
x=\frac{4y}{3}+2
Solve for y
y=\frac{3\left(x-2\right)}{4}
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6x=12+8y
Add 8y to both sides.
6x=8y+12
The equation is in standard form.
\frac{6x}{6}=\frac{8y+12}{6}
Divide both sides by 6.
x=\frac{8y+12}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{4y}{3}+2
Divide 12+8y by 6.
-8y=12-6x
Subtract 6x from both sides.
\frac{-8y}{-8}=\frac{12-6x}{-8}
Divide both sides by -8.
y=\frac{12-6x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{3x}{4}-\frac{3}{2}
Divide 12-6x by -8.
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