Solve for x
x\leq \frac{10}{3}
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6x\leq 9+11
Add 11 to both sides.
6x\leq 20
Add 9 and 11 to get 20.
x\leq \frac{20}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
x\leq \frac{10}{3}
Reduce the fraction \frac{20}{6} to lowest terms by extracting and canceling out 2.
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