Solve for x
x=\frac{10}{19}\approx 0.526315789
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12xx-3\left(3-\left(7x+1\right)\right)=12x\left(x-3\right)+24
Multiply both sides of the equation by 6, the least common multiple of 3,2.
12x^{2}-3\left(3-\left(7x+1\right)\right)=12x\left(x-3\right)+24
Multiply x and x to get x^{2}.
12x^{2}-3\left(3-7x-1\right)=12x\left(x-3\right)+24
To find the opposite of 7x+1, find the opposite of each term.
12x^{2}-3\left(2-7x\right)=12x\left(x-3\right)+24
Subtract 1 from 3 to get 2.
12x^{2}-6+21x=12x\left(x-3\right)+24
Use the distributive property to multiply -3 by 2-7x.
12x^{2}-6+21x=12x^{2}-36x+24
Use the distributive property to multiply 12x by x-3.
12x^{2}-6+21x-12x^{2}=-36x+24
Subtract 12x^{2} from both sides.
-6+21x=-36x+24
Combine 12x^{2} and -12x^{2} to get 0.
-6+21x+36x=24
Add 36x to both sides.
-6+57x=24
Combine 21x and 36x to get 57x.
57x=24+6
Add 6 to both sides.
57x=30
Add 24 and 6 to get 30.
x=\frac{30}{57}
Divide both sides by 57.
x=\frac{10}{19}
Reduce the fraction \frac{30}{57} to lowest terms by extracting and canceling out 3.
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