Solve 6x(1/3-1/2)-3^2div(-12)

$$6 x ( \frac { 1 } { 3 } - \frac { 1 } { 2 } ) - 3 ^ { 2 } \div ( - 12 )$$

Evaluate

$$\frac{3}{4}-x$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$6x\left(\frac{2}{6}-\frac{3}{6}\right)-\frac{3^{2}}{-12}$$

Since \frac{2}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$6x\times \frac{2-3}{6}-\frac{3^{2}}{-12}$$

Subtract 3 from 2 to get -1.

$$6x\left(-\frac{1}{6}\right)-\frac{3^{2}}{-12}$$

Cancel out 6 and 6.

$$-x-\frac{3^{2}}{-12}$$

Calculate 3 to the power of 2 and get 9.

$$-x-\frac{9}{-12}$$

Reduce the fraction \frac{9}{-12} to lowest terms by extracting and canceling out 3.

$$-x-\left(-\frac{3}{4}\right)$$

The opposite of -\frac{3}{4} is \frac{3}{4}.

$$-x+\frac{3}{4}$$

Expand

$$\frac{3}{4}-x$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$6x\left(\frac{2}{6}-\frac{3}{6}\right)-\frac{3^{2}}{-12}$$

Since \frac{2}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$6x\times \frac{2-3}{6}-\frac{3^{2}}{-12}$$

Subtract 3 from 2 to get -1.

$$6x\left(-\frac{1}{6}\right)-\frac{3^{2}}{-12}$$

Cancel out 6 and 6.

$$-x-\frac{3^{2}}{-12}$$

Calculate 3 to the power of 2 and get 9.

$$-x-\frac{9}{-12}$$

Reduce the fraction \frac{9}{-12} to lowest terms by extracting and canceling out 3.

$$-x-\left(-\frac{3}{4}\right)$$

The opposite of -\frac{3}{4} is \frac{3}{4}.

$$-x+\frac{3}{4}$$