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x^{2}-4=0
Divide both sides by 6.
\left(x-2\right)\left(x+2\right)=0
Consider x^{2}-4. Rewrite x^{2}-4 as x^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=2 x=-2
To find equation solutions, solve x-2=0 and x+2=0.
6x^{2}=24
Add 24 to both sides. Anything plus zero gives itself.
x^{2}=\frac{24}{6}
Divide both sides by 6.
x^{2}=4
Divide 24 by 6 to get 4.
x=2 x=-2
Take the square root of both sides of the equation.
6x^{2}-24=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 6\left(-24\right)}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and -24 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 6\left(-24\right)}}{2\times 6}
Square 0.
x=\frac{0±\sqrt{-24\left(-24\right)}}{2\times 6}
Multiply -4 times 6.
x=\frac{0±\sqrt{576}}{2\times 6}
Multiply -24 times -24.
x=\frac{0±24}{2\times 6}
Take the square root of 576.
x=\frac{0±24}{12}
Multiply 2 times 6.
x=2
Now solve the equation x=\frac{0±24}{12} when ± is plus. Divide 24 by 12.
x=-2
Now solve the equation x=\frac{0±24}{12} when ± is minus. Divide -24 by 12.
x=2 x=-2
The equation is now solved.