Solve 6x^2=540

$$6 x ^ { 2 } = 540$$

Solve for x

$$x=3\sqrt{10}\approx 9.486832981$$

$$x=-3\sqrt{10}\approx -9.486832981$$

Steps by Finding Square Root

Divide both sides by 6.

$$x^{2}=\frac{540}{6}$$

Divide 540 by 6 to get 90.

$$x^{2}=90$$

Take the square root of both sides of the equation.

$$x=3\sqrt{10} x=-3\sqrt{10}$$

Steps Using the Quadratic Formula

Divide both sides by 6.

$$x^{2}=\frac{540}{6}$$

Divide 540 by 6 to get 90.

$$x^{2}=90$$

Subtract 90 from both sides.

$$x^{2}-90=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -90 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-90\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-90\right)}}{2}$$

Multiply -4 times -90.

$$x=\frac{0±\sqrt{360}}{2}$$

Take the square root of 360.

$$x=\frac{0±6\sqrt{10}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{10}}{2} when ± is plus.

$$x=3\sqrt{10}$$

Now solve the equation x=\frac{0±6\sqrt{10}}{2} when ± is minus.

$$x=-3\sqrt{10}$$

The equation is now solved.

$$x=3\sqrt{10} x=-3\sqrt{10}$$