Solve 6x^2+7*2x=0

$$6 x ^ { 2 } + 7 \cdot 2 x = 0$$

Solve for x

$$x = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

$$x=0$$

Steps Using Factoring

Factor out x.

$$x\left(6x+2\times 7\right)=0$$

To find equation solutions, solve x=0 and 6x+14=0.

$$x=0 x=-\frac{7}{3}$$

Steps Using the Quadratic Formula

Multiply 7 and 2 to get 14.

$$6x^{2}+14x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 14 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-14±\sqrt{14^{2}}}{2\times 6}$$

Take the square root of 14^{2}.

$$x=\frac{-14±14}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{-14±14}{12}$$

Now solve the equation x=\frac{-14±14}{12} when ± is plus. Add -14 to 14.

$$x=\frac{0}{12}$$

Divide 0 by 12.

$$x=0$$

Now solve the equation x=\frac{-14±14}{12} when ± is minus. Subtract 14 from -14.

$$x=-\frac{28}{12}$$

Reduce the fraction \frac{-28}{12} to lowest terms by extracting and canceling out 4.

$$x=-\frac{7}{3}$$

The equation is now solved.

$$x=0 x=-\frac{7}{3}$$

Steps for Completing the Square

Multiply 7 and 2 to get 14.

$$6x^{2}+14x=0$$

Divide both sides by 6.

$$\frac{6x^{2}+14x}{6}=\frac{0}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x^{2}+\frac{14}{6}x=\frac{0}{6}$$

Reduce the fraction \frac{14}{6} to lowest terms by extracting and canceling out 2.

$$x^{2}+\frac{7}{3}x=\frac{0}{6}$$

Divide 0 by 6.

$$x^{2}+\frac{7}{3}x=0$$

Divide \frac{7}{3}, the coefficient of the x term, by 2 to get \frac{7}{6}. Then add the square of \frac{7}{6} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+\frac{7}{3}x+\left(\frac{7}{6}\right)^{2}=\left(\frac{7}{6}\right)^{2}$$

Square \frac{7}{6} by squaring both the numerator and the denominator of the fraction.

$$x^{2}+\frac{7}{3}x+\frac{49}{36}=\frac{49}{36}$$

Factor x^{2}+\frac{7}{3}x+\frac{49}{36}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{7}{6}\right)^{2}=\frac{49}{36}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+\frac{7}{6}\right)^{2}}=\sqrt{\frac{49}{36}}$$

Simplify.

$$x+\frac{7}{6}=\frac{7}{6} x+\frac{7}{6}=-\frac{7}{6}$$

Subtract \frac{7}{6} from both sides of the equation.

$$x=0 x=-\frac{7}{3}$$