Solve for x
x=-\frac{7y}{6}-\frac{7}{3}
Solve for y
y=-\frac{6x}{7}-2
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6x+14=-7y
Subtract 7y from both sides. Anything subtracted from zero gives its negation.
6x=-7y-14
Subtract 14 from both sides.
\frac{6x}{6}=\frac{-7y-14}{6}
Divide both sides by 6.
x=\frac{-7y-14}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{7y}{6}-\frac{7}{3}
Divide -7y-14 by 6.
7y+14=-6x
Subtract 6x from both sides. Anything subtracted from zero gives its negation.
7y=-6x-14
Subtract 14 from both sides.
\frac{7y}{7}=\frac{-6x-14}{7}
Divide both sides by 7.
y=\frac{-6x-14}{7}
Dividing by 7 undoes the multiplication by 7.
y=-\frac{6x}{7}-2
Divide -6x-14 by 7.
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