Solve for x
x=-\frac{2y}{3}+\frac{3}{2}
Solve for y
y=-\frac{3x}{2}+\frac{9}{4}
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6x-9=-4y
Subtract 4y from both sides. Anything subtracted from zero gives its negation.
6x=-4y+9
Add 9 to both sides.
6x=9-4y
The equation is in standard form.
\frac{6x}{6}=\frac{9-4y}{6}
Divide both sides by 6.
x=\frac{9-4y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{2y}{3}+\frac{3}{2}
Divide -4y+9 by 6.
4y-9=-6x
Subtract 6x from both sides. Anything subtracted from zero gives its negation.
4y=-6x+9
Add 9 to both sides.
4y=9-6x
The equation is in standard form.
\frac{4y}{4}=\frac{9-6x}{4}
Divide both sides by 4.
y=\frac{9-6x}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3x}{2}+\frac{9}{4}
Divide -6x+9 by 4.
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