Solve for x
x=\frac{4-y}{3}
Solve for y
y=4-3x
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6x-8=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
6x=-2y+8
Add 8 to both sides.
6x=8-2y
The equation is in standard form.
\frac{6x}{6}=\frac{8-2y}{6}
Divide both sides by 6.
x=\frac{8-2y}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{4-y}{3}
Divide -2y+8 by 6.
2y-8=-6x
Subtract 6x from both sides. Anything subtracted from zero gives its negation.
2y=-6x+8
Add 8 to both sides.
2y=8-6x
The equation is in standard form.
\frac{2y}{2}=\frac{8-6x}{2}
Divide both sides by 2.
y=\frac{8-6x}{2}
Dividing by 2 undoes the multiplication by 2.
y=4-3x
Divide -6x+8 by 2.
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