Solve for x
x\leq \frac{25}{2}
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8x\leq 100
Combine 6x and 2x to get 8x.
x\leq \frac{100}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
x\leq \frac{25}{2}
Reduce the fraction \frac{100}{8} to lowest terms by extracting and canceling out 4.
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