Solve 6ab*(-8a^2b)

$$6 a b \times ( - 8 a ^ { 2 } b )$$

Evaluate

$$-48b^{2}a^{3}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$6^{1}a^{1}b^{1}\left(-8\right)^{1}a^{2}b^{1}$$

Use the Commutative Property of Multiplication.

$$6^{1}\left(-8\right)^{1}a^{1}a^{2}b^{1}b^{1}$$

To multiply powers of the same base, add their exponents.

$$6^{1}\left(-8\right)^{1}a^{1+2}b^{1+1}$$

Add the exponents 1 and 2.

$$6^{1}\left(-8\right)^{1}a^{3}b^{1+1}$$

Add the exponents 1 and 1.

$$6^{1}\left(-8\right)^{1}a^{3}b^{2}$$

Multiply 6 times -8.

$$-48a^{3}b^{2}$$

Differentiate w.r.t. a

$$-144\left(ab\right)^{2}$$