Solve 6a-3b=1

$$6 a - 3 b = 1$$

Solve for a

$$a=\frac{b}{2}+\frac{1}{6}$$

Steps for Solving Linear Equation

Add 3b to both sides.

$$6a=1+3b$$

The equation is in standard form.

$$6a=3b+1$$

Divide both sides by 6.

$$\frac{6a}{6}=\frac{3b+1}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$a=\frac{3b+1}{6}$$

Divide 1+3b by 6.

$$a=\frac{b}{2}+\frac{1}{6}$$

Solve for b

$$b=2a-\frac{1}{3}$$

Steps for Solving Linear Equation

Subtract 6a from both sides.

$$-3b=1-6a$$

Divide both sides by -3.

$$\frac{-3b}{-3}=\frac{1-6a}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$b=\frac{1-6a}{-3}$$

Divide 1-6a by -3.

$$b=2a-\frac{1}{3}$$