Solve 6-4^2+2k-3

$$6 - 4 ^ { 2 } + 2 k - 3$$

Evaluate

$$2k-13$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$6-16+2k-3$$

Subtract 16 from 6 to get -10.

$$-10+2k-3$$

Subtract 3 from -10 to get -13.

$$-13+2k$$

Differentiate w.r.t. k

$$2$$

Steps Using Derivative Rule for Sum

Calculate 4 to the power of 2 and get 16.

$$\frac{\mathrm{d}}{\mathrm{d}k}(6-16+2k-3)$$

Subtract 16 from 6 to get -10.

$$\frac{\mathrm{d}}{\mathrm{d}k}(-10+2k-3)$$

Subtract 3 from -10 to get -13.

$$\frac{\mathrm{d}}{\mathrm{d}k}(-13+2k)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2k^{1-1}$$

Subtract 1 from 1.

$$2k^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$