Solve 6-2k=2*(8/9+3)

$$6 - 2 k = 2 \cdot ( \frac { 8 } { 9 } + 3 )$$

Solve for k

$$k=-\frac{8}{9}\approx -0.888888889$$

Steps for Solving Linear Equation

Convert 3 to fraction \frac{27}{9}.

$$6-2k=2\left(\frac{8}{9}+\frac{27}{9}\right)$$

Since \frac{8}{9} and \frac{27}{9} have the same denominator, add them by adding their numerators.

$$6-2k=2\times \frac{8+27}{9}$$

Add 8 and 27 to get 35.

$$6-2k=2\times \frac{35}{9}$$

Express 2\times \frac{35}{9} as a single fraction.

$$6-2k=\frac{2\times 35}{9}$$

Multiply 2 and 35 to get 70.

$$6-2k=\frac{70}{9}$$

Subtract 6 from both sides.

$$-2k=\frac{70}{9}-6$$

Convert 6 to fraction \frac{54}{9}.

$$-2k=\frac{70}{9}-\frac{54}{9}$$

Since \frac{70}{9} and \frac{54}{9} have the same denominator, subtract them by subtracting their numerators.

$$-2k=\frac{70-54}{9}$$

Subtract 54 from 70 to get 16.

$$-2k=\frac{16}{9}$$

Divide both sides by -2.

$$k=\frac{\frac{16}{9}}{-2}$$

Express \frac{\frac{16}{9}}{-2} as a single fraction.

$$k=\frac{16}{9\left(-2\right)}$$

Multiply 9 and -2 to get -18.

$$k=\frac{16}{-18}$$

Reduce the fraction \frac{16}{-18} to lowest terms by extracting and canceling out 2.

$$k=-\frac{8}{9}$$