Solve 6-[16*6-(118-21)]div3+864div(16+132div12)

$$6 - [ 16 \times 6 - ( 118 - 21 ) ] \div 3 + 864 \div ( 16 + 132 \div 12 )$$

Evaluate

$$\frac{115}{3}\approx 38.333333333$$

Solution Steps

Multiply 16 and 6 to get 96.

$$6-\frac{96-\left(118-21\right)}{3}+\frac{864}{16+\frac{132}{12}}$$

Subtract 21 from 118 to get 97.

$$6-\frac{96-97}{3}+\frac{864}{16+\frac{132}{12}}$$

Subtract 97 from 96 to get -1.

$$6-\frac{-1}{3}+\frac{864}{16+\frac{132}{12}}$$

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$6-\left(-\frac{1}{3}\right)+\frac{864}{16+\frac{132}{12}}$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$6+\frac{1}{3}+\frac{864}{16+\frac{132}{12}}$$

Convert 6 to fraction \frac{18}{3}.

$$\frac{18}{3}+\frac{1}{3}+\frac{864}{16+\frac{132}{12}}$$

Since \frac{18}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{18+1}{3}+\frac{864}{16+\frac{132}{12}}$$

Add 18 and 1 to get 19.

$$\frac{19}{3}+\frac{864}{16+\frac{132}{12}}$$

Divide 132 by 12 to get 11.

$$\frac{19}{3}+\frac{864}{16+11}$$

Add 16 and 11 to get 27.

$$\frac{19}{3}+\frac{864}{27}$$

Divide 864 by 27 to get 32.

$$\frac{19}{3}+32$$

Convert 32 to fraction \frac{96}{3}.

$$\frac{19}{3}+\frac{96}{3}$$

Since \frac{19}{3} and \frac{96}{3} have the same denominator, add them by adding their numerators.

$$\frac{19+96}{3}$$

Add 19 and 96 to get 115.

$$\frac{115}{3}$$

Factor

$$\frac{5 \cdot 23}{3} = 38\frac{1}{3} = 38.333333333333336$$