Solve for x
x\geq 12
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8-3x\leq \frac{-168}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
8-3x\leq -28
Divide -168 by 6 to get -28.
-3x\leq -28-8
Subtract 8 from both sides.
-3x\leq -36
Subtract 8 from -28 to get -36.
x\geq \frac{-36}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\geq 12
Divide -36 by -3 to get 12.
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