Solve 6(3k+5)=39

$$6 ( 3 k + 5 ) = 39$$

Solve for k

$$k=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Divide both sides by 6.

$$3k+5=\frac{39}{6}$$

Reduce the fraction \frac{39}{6} to lowest terms by extracting and canceling out 3.

$$3k+5=\frac{13}{2}$$

Subtract 5 from both sides.

$$3k=\frac{13}{2}-5$$

Convert 5 to fraction \frac{10}{2}.

$$3k=\frac{13}{2}-\frac{10}{2}$$

Since \frac{13}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$3k=\frac{13-10}{2}$$

Subtract 10 from 13 to get 3.

$$3k=\frac{3}{2}$$

Divide both sides by 3.

$$k=\frac{\frac{3}{2}}{3}$$

Express \frac{\frac{3}{2}}{3} as a single fraction.

$$k=\frac{3}{2\times 3}$$

Cancel out 3 in both numerator and denominator.

$$k=\frac{1}{2}$$