Solve 6(2)^2+3(2)(-3)-(-3)^2

$$6 ( 2 ) ^ { 2 } + 3 ( 2 ) ( - 3 ) - ( - 3 ) ^ { 2 }$$

Evaluate

$$-3$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$6\times 4+3\times 2\left(-3\right)-\left(-3\right)^{2}$$

Multiply 6 and 4 to get 24.

$$24+3\times 2\left(-3\right)-\left(-3\right)^{2}$$

Multiply 3 and 2 to get 6.

$$24+6\left(-3\right)-\left(-3\right)^{2}$$

Multiply 6 and -3 to get -18.

$$24-18-\left(-3\right)^{2}$$

Subtract 18 from 24 to get 6.

$$6-\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$6-9$$

Subtract 9 from 6 to get -3.

$$-3$$

Factor

$$-3$$